x^2-52x+36=0

Solution for x^2-52x+36=0 equation:

x^2-52x+36=0

a = 1; b = -52; c = +36;
Δ = b2-4ac
Δ = -522-4·1·36
Δ = 2560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2560}=\sqrt{256*10}=\sqrt{256}*\sqrt{10}=16\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-16\sqrt{10}}{2*1}=\frac{52-16\sqrt{10}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+16\sqrt{10}}{2*1}=\frac{52+16\sqrt{10}}{2}
$